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    Number of Students Doing Homework at a Given Time

    less than 1 minute read

    <-E 1450> Number of Students Doing Homework at a Given Time

    class Solution {
    public:
        int busyStudent(vector<int>& startTime, vector<int>& endTime, int queryTime) {
            int ans = 0;
            for(int i = 0; i != startTime.size(); i++) {
                if(startTime[i] <= queryTime)
                    if(endTime[i] >= queryTime)
                        ans++;
                        
            }
            return ans;
        }
    };
    

    Tags: Algorithms, C++, Leetcode

    Updated: November 27, 2020

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